ASVAB Arithmetic Reasoning Practice Test 116303 Results

Your Results Global Average
Questions 5 5
Correct 0 3.02
Score 0% 60%

Review

1

Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 17 small cakes per hour. The kitchen is available for 4 hours and 26 large cakes and 190 small cakes need to be baked.

How many cooks are required to bake the required number of cakes during the time the kitchen is available?

41% Answer Correctly
13
5
9
8

Solution

If a single cook can bake 4 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 4 x 4 = 16 large cakes during that time. 26 large cakes are needed for the party so \( \frac{26}{16} \) = 1\(\frac{5}{8}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 17 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 17 x 4 = 68 small cakes during that time. 190 small cakes are needed for the party so \( \frac{190}{68} \) = 2\(\frac{27}{34}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 2 + 3 = 5 cooks.


2

Solve for \( \frac{3!}{4!} \)

67% Answer Correctly
\( \frac{1}{4} \)
\( \frac{1}{9} \)
\( \frac{1}{120} \)
8

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)


3

53% Answer Correctly
6.0
1
4.5
0.6

Solution


1


4

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

60% Answer Correctly

associative

distributive

commutative

PEDMAS


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


5

How many 10-passenger vans will it take to drive all 94 members of the football team to an away game?

81% Answer Correctly
7 vans
10 vans
4 vans
3 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{94}{10} \) = 9\(\frac{2}{5}\)

So, it will take 9 full vans and one partially full van to transport the entire team making a total of 10 vans.