ASVAB Arithmetic Reasoning Practice Test 116439 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

What is \( 9 \)\( \sqrt{28} \) + \( 5 \)\( \sqrt{7} \)

35% Answer Correctly
45\( \sqrt{4} \)
14\( \sqrt{28} \)
23\( \sqrt{7} \)
14\( \sqrt{196} \)

Solution

To add these radicals together their radicands must be the same:

9\( \sqrt{28} \) + 5\( \sqrt{7} \)
9\( \sqrt{4 \times 7} \) + 5\( \sqrt{7} \)
9\( \sqrt{2^2 \times 7} \) + 5\( \sqrt{7} \)
(9)(2)\( \sqrt{7} \) + 5\( \sqrt{7} \)
18\( \sqrt{7} \) + 5\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

18\( \sqrt{7} \) + 5\( \sqrt{7} \)
(18 + 5)\( \sqrt{7} \)
23\( \sqrt{7} \)


2

4! = ?

85% Answer Correctly

4 x 3 x 2 x 1

5 x 4 x 3 x 2 x 1

4 x 3

3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


3

What is 7b3 - 6b3?

71% Answer Correctly
-b-3
13b9
b3
13b6

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

7b3 - 6b3
(7 - 6)b3
b3


4

What is \( \frac{4}{8} \) ÷ \( \frac{1}{7} \)?

68% Answer Correctly
3\(\frac{1}{2}\)
\(\frac{3}{28}\)
\(\frac{2}{25}\)
\(\frac{8}{27}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{8} \) ÷ \( \frac{1}{7} \) = \( \frac{4}{8} \) x \( \frac{7}{1} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{8} \) x \( \frac{7}{1} \) = \( \frac{4 x 7}{8 x 1} \) = \( \frac{28}{8} \) = 3\(\frac{1}{2}\)


5

What is 4a4 + 8a4?

66% Answer Correctly
12a8
12a-8
12a4
-4a-4

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

4a4 + 8a4
(4 + 8)a4
12a4