ASVAB Arithmetic Reasoning Practice Test 120863 Results

Your Results Global Average
Questions 5 5
Correct 0 3.53
Score 0% 71%

Review

1

What is \( \frac{6\sqrt{9}}{3\sqrt{3}} \)?

71% Answer Correctly
\(\frac{1}{3}\) \( \sqrt{\frac{1}{2}} \)
2 \( \sqrt{\frac{1}{3}} \)
3 \( \sqrt{\frac{1}{2}} \)
2 \( \sqrt{3} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{6\sqrt{9}}{3\sqrt{3}} \)
\( \frac{6}{3} \) \( \sqrt{\frac{9}{3}} \)
2 \( \sqrt{3} \)


2

Solve 4 + (4 + 5) ÷ 3 x 3 - 32

52% Answer Correctly
1\(\frac{1}{6}\)
1\(\frac{1}{3}\)
2
4

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (4 + 5) ÷ 3 x 3 - 32
P: 4 + (9) ÷ 3 x 3 - 32
E: 4 + 9 ÷ 3 x 3 - 9
MD: 4 + \( \frac{9}{3} \) x 3 - 9
MD: 4 + \( \frac{27}{3} \) - 9
AS: \( \frac{12}{3} \) + \( \frac{27}{3} \) - 9
AS: \( \frac{39}{3} \) - 9
AS: \( \frac{39 - 27}{3} \)
\( \frac{12}{3} \)
4


3

What is the distance in miles of a trip that takes 4 hours at an average speed of 20 miles per hour?

87% Answer Correctly
80 miles
200 miles
150 miles
405 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 20mph \times 4h \)
80 miles


4

17 members of a bridal party need transported to a wedding reception but there are only 4 4-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
6
8
2
1

Solution

There are 4 4-passenger taxis available so that's 4 x 4 = 16 total seats. There are 17 people needing transportation leaving 17 - 16 = 1 who will have to find other transportation.


5

Which of the following is an improper fraction?

70% Answer Correctly

\(1 {2 \over 5} \)

\({a \over 5} \)

\({7 \over 5} \)

\({2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.