The equation for this sequence is:

a_n = a_n-1 + 4(n - 1)

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 4(6 - 1)
a₆ = 41 + 4(5)
a₆ = 61

By buying two shirts, Alex will save $36 x \( \frac{5}{100} \) = \( \frac{$36 x 5}{100} \) = \( \frac{$180}{100} \) = $1.80 on the second shirt.

If a single cook can bake 2 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 2 x 4 = 8 large cakes during that time. 32 large cakes are needed for the party so \( \frac{32}{8} \) = 4 cooks are needed to bake the required number of large cakes.

If a single cook can bake 10 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 10 x 4 = 40 small cakes during that time. 190 small cakes are needed for the party so \( \frac{190}{40} \) = 4\(\frac{3}{4}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 4 + 5 = 9 cooks.

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (4 + 3) ÷ 2 x 5 - 3²
P: 2 + (7) ÷ 2 x 5 - 3²
E: 2 + 7 ÷ 2 x 5 - 9
MD: 2 + \( \frac{7}{2} \) x 5 - 9
MD: 2 + \( \frac{35}{2} \) - 9
AS: \( \frac{4}{2} \) + \( \frac{35}{2} \) - 9
AS: \( \frac{39}{2} \) - 9
AS: \( \frac{39 - 18}{2} \)
\( \frac{21}{2} \)
10\(\frac{1}{2}\)

49% of the water consumption is industrial use and 22% is personal use so (49% - 22%) = 27% more water is used for industrial purposes. 25,000 gallons are consumed daily so industry consumes \( \frac{27}{100} \) x 25,000 gallons = 6,750 gallons.