| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
Find the average of the following numbers: 12, 6, 13, 5.
| 12 | |
| 9 | |
| 10 | |
| 14 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{12 + 6 + 13 + 5}{4} \) = \( \frac{36}{4} \) = 9
The __________ is the smallest positive integer that is a multiple of two or more integers.
least common multiple |
|
absolute value |
|
least common factor |
|
greatest common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
Bob loaned Frank $400 at an annual interest rate of 5%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $25 | |
| $84 | |
| $40 | |
| $20 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $400
i = 0.05 x $400
i = $20
What is -6a3 + 8a3?
| 2a3 | |
| 2a6 | |
| 14a3 | |
| -14a-3 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-6a3 + 8a3
(-6 + 8)a3
2a3
If a rectangle is twice as long as it is wide and has a perimeter of 18 meters, what is the area of the rectangle?
| 72 m2 | |
| 162 m2 | |
| 18 m2 | |
| 50 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 18 meters so the equation becomes: 2w + 2h = 18.
Putting these two equations together and solving for width (w):
2w + 2h = 18
w + h = \( \frac{18}{2} \)
w + h = 9
w = 9 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 9 - 2w
3w = 9
w = \( \frac{9}{3} \)
w = 3
Since h = 2w that makes h = (2 x 3) = 6 and the area = h x w = 3 x 6 = 18 m2