| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
The total water usage for a city is 30,000 gallons each day. Of that total, 21% is for personal use and 33% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 6,750 | |
| 3,600 | |
| 8,700 | |
| 1,450 |
33% of the water consumption is industrial use and 21% is personal use so (33% - 21%) = 12% more water is used for industrial purposes. 30,000 gallons are consumed daily so industry consumes \( \frac{12}{100} \) x 30,000 gallons = 3,600 gallons.
Simplify \( \frac{32}{60} \).
| \( \frac{8}{17} \) | |
| \( \frac{7}{19} \) | |
| \( \frac{8}{15} \) | |
| \( \frac{5}{19} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{32}{60} \) = \( \frac{\frac{32}{4}}{\frac{60}{4}} \) = \( \frac{8}{15} \)
The __________ is the smallest positive integer that is a multiple of two or more integers.
least common factor |
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least common multiple |
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greatest common factor |
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absolute value |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
Solve 5 + (3 + 2) ÷ 3 x 4 - 32
| 1\(\frac{2}{5}\) | |
| 3 | |
| 2\(\frac{2}{3}\) | |
| 2 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (3 + 2) ÷ 3 x 4 - 32
P: 5 + (5) ÷ 3 x 4 - 32
E: 5 + 5 ÷ 3 x 4 - 9
MD: 5 + \( \frac{5}{3} \) x 4 - 9
MD: 5 + \( \frac{20}{3} \) - 9
AS: \( \frac{15}{3} \) + \( \frac{20}{3} \) - 9
AS: \( \frac{35}{3} \) - 9
AS: \( \frac{35 - 27}{3} \)
\( \frac{8}{3} \)
2\(\frac{2}{3}\)
Solve for \( \frac{2!}{6!} \)
| \( \frac{1}{360} \) | |
| \( \frac{1}{1680} \) | |
| 30 | |
| 210 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)