If the tiger has consumed 54 pounds of food in 6 days that's \( \frac{54}{6} \) = 9 pounds of food per day. The tiger needs to consume 90 - 54 = 36 more pounds of food to reach 90 pounds total. At 9 pounds of food per day that's \( \frac{36}{9} \) = 4 more days.

To subtract these radicals together their radicands must be the same:

6\( \sqrt{32} \) - 4\( \sqrt{2} \)
6\( \sqrt{16 \times 2} \) - 4\( \sqrt{2} \)
6\( \sqrt{4^2 \times 2} \) - 4\( \sqrt{2} \)
(6)(4)\( \sqrt{2} \) - 4\( \sqrt{2} \)
24\( \sqrt{2} \) - 4\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{16}{81}} \)
\( \frac{\sqrt{16}}{\sqrt{81}} \)
\( \frac{\sqrt{4^2}}{\sqrt{9^2}} \)
\(\frac{4}{9}\)

To add these radicals together their radicands must be the same:

8\( \sqrt{8} \) + 5\( \sqrt{2} \)
8\( \sqrt{4 \times 2} \) + 5\( \sqrt{2} \)
8\( \sqrt{2^2 \times 2} \) + 5\( \sqrt{2} \)
(8)(2)\( \sqrt{2} \) + 5\( \sqrt{2} \)
16\( \sqrt{2} \) + 5\( \sqrt{2} \)

Now that the radicands are identical, you can add them together: