| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.76 |
| Score | 0% | 55% |
A circular logo is enlarged to fit the lid of a jar. The new diameter is 70% larger than the original. By what percentage has the area of the logo increased?
| 15% | |
| 35% | |
| 17\(\frac{1}{2}\)% | |
| 32\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 70% the radius (and, consequently, the total area) increases by \( \frac{70\text{%}}{2} \) = 35%
Solve 3 + (4 + 3) ÷ 4 x 5 - 22
| 7\(\frac{3}{4}\) | |
| \(\frac{5}{7}\) | |
| 1\(\frac{3}{5}\) | |
| \(\frac{3}{8}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (4 + 3) ÷ 4 x 5 - 22
P: 3 + (7) ÷ 4 x 5 - 22
E: 3 + 7 ÷ 4 x 5 - 4
MD: 3 + \( \frac{7}{4} \) x 5 - 4
MD: 3 + \( \frac{35}{4} \) - 4
AS: \( \frac{12}{4} \) + \( \frac{35}{4} \) - 4
AS: \( \frac{47}{4} \) - 4
AS: \( \frac{47 - 16}{4} \)
\( \frac{31}{4} \)
7\(\frac{3}{4}\)
What is 8\( \sqrt{9} \) x 8\( \sqrt{6} \)?
| 192\( \sqrt{6} \) | |
| 16\( \sqrt{6} \) | |
| 64\( \sqrt{6} \) | |
| 16\( \sqrt{9} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
8\( \sqrt{9} \) x 8\( \sqrt{6} \)
(8 x 8)\( \sqrt{9 \times 6} \)
64\( \sqrt{54} \)
Now we need to simplify the radical:
64\( \sqrt{54} \)
64\( \sqrt{6 \times 9} \)
64\( \sqrt{6 \times 3^2} \)
(64)(3)\( \sqrt{6} \)
192\( \sqrt{6} \)
Which of the following is not an integer?
1 |
|
-1 |
|
0 |
|
\({1 \over 2}\) |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
How many 2 gallon cans worth of fuel would you need to pour into an empty 20 gallon tank to fill it exactly halfway?
| 9 | |
| 10 | |
| 2 | |
| 5 |
To fill a 20 gallon tank exactly halfway you'll need 10 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{10 \text{ gallons}}{2 \text{ gallons}} \) = 5