ASVAB Arithmetic Reasoning Practice Test 125845 Results

Your Results Global Average
Questions 5 5
Correct 0 3.03
Score 0% 61%

Review

1

What is \( \frac{4}{9} \) ÷ \( \frac{4}{5} \)?

68% Answer Correctly
\(\frac{4}{27}\)
\(\frac{1}{49}\)
\(\frac{1}{35}\)
\(\frac{5}{9}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{4}{9} \) ÷ \( \frac{4}{5} \) = \( \frac{4}{9} \) x \( \frac{5}{4} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{9} \) x \( \frac{5}{4} \) = \( \frac{4 x 5}{9 x 4} \) = \( \frac{20}{36} \) = \(\frac{5}{9}\)


2

What is \( 6 \)\( \sqrt{48} \) + \( 6 \)\( \sqrt{3} \)

35% Answer Correctly
36\( \sqrt{48} \)
36\( \sqrt{144} \)
30\( \sqrt{3} \)
12\( \sqrt{144} \)

Solution

To add these radicals together their radicands must be the same:

6\( \sqrt{48} \) + 6\( \sqrt{3} \)
6\( \sqrt{16 \times 3} \) + 6\( \sqrt{3} \)
6\( \sqrt{4^2 \times 3} \) + 6\( \sqrt{3} \)
(6)(4)\( \sqrt{3} \) + 6\( \sqrt{3} \)
24\( \sqrt{3} \) + 6\( \sqrt{3} \)

Now that the radicands are identical, you can add them together:

24\( \sqrt{3} \) + 6\( \sqrt{3} \)
(24 + 6)\( \sqrt{3} \)
30\( \sqrt{3} \)


3

How many 12-passenger vans will it take to drive all 58 members of the football team to an away game?

81% Answer Correctly
7 vans
5 vans
8 vans
6 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{58}{12} \) = 4\(\frac{5}{6}\)

So, it will take 4 full vans and one partially full van to transport the entire team making a total of 5 vans.


4

Which of the following statements about exponents is false?

47% Answer Correctly

b0 = 1

b1 = 1

b1 = b

all of these are false


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


5

What is the least common multiple of 3 and 5?

72% Answer Correctly
2
11
15
6

Solution

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 have in common.