ASVAB Arithmetic Reasoning Practice Test 125957 Results

Your Results Global Average
Questions 5 5
Correct 0 3.45
Score 0% 69%

Review

1

Which of the following is not an integer?

77% Answer Correctly

\({1 \over 2}\)

0

-1

1


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


2

Simplify \( \frac{20}{44} \).

77% Answer Correctly
\( \frac{5}{11} \)
\( \frac{7}{11} \)
\( \frac{1}{2} \)
\( \frac{4}{11} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 44 are [1, 2, 4, 11, 22, 44]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{20}{44} \) = \( \frac{\frac{20}{4}}{\frac{44}{4}} \) = \( \frac{5}{11} \)


3

A circular logo is enlarged to fit the lid of a jar. The new diameter is 35% larger than the original. By what percentage has the area of the logo increased?

51% Answer Correctly
15%
17\(\frac{1}{2}\)%
35%
30%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 35% the radius (and, consequently, the total area) increases by \( \frac{35\text{%}}{2} \) = 17\(\frac{1}{2}\)%


4

Ezra loaned Betty $1,300 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$1,391
$1,378
$1,404
$1,326

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,300
i = 0.06 x $1,300

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,300 + $78
total = $1,378


5

What is 2b4 + 9b4?

66% Answer Correctly
7b4
11b-8
11b16
11b4

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

2b4 + 9b4
(2 + 9)b4
11b4