ASVAB Arithmetic Reasoning Practice Test 126148 Results

Your Results Global Average
Questions 5 5
Correct 0 3.40
Score 0% 68%

Review

1

Which of the following is not a prime number?

65% Answer Correctly

2

9

7

5


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


2

What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?

69% Answer Correctly
31
28
26
23

Solution

The equation for this sequence is:

an = an-1 + 2(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31


3

What is \( \frac{3}{8} \) - \( \frac{6}{16} \)?

61% Answer Correctly
1 \( \frac{5}{14} \)
2 \( \frac{1}{16} \)
2 \( \frac{5}{11} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 16 are [16, 32, 48, 64, 80, 96]. The first few multiples they share are [16, 32, 48, 64, 80] making 16 the smallest multiple 8 and 16 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{3 x 2}{8 x 2} \) - \( \frac{6 x 1}{16 x 1} \)

\( \frac{6}{16} \) - \( \frac{6}{16} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{6 - 6}{16} \) = \( \frac{0}{16} \) =


4

What is 5c2 x 3c2?

75% Answer Correctly
15c0
15c2
8c4
15c4

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

5c2 x 3c2
(5 x 3)c(2 + 2)
15c4


5

What is \( \frac{2}{6} \) x \( \frac{1}{9} \)?

72% Answer Correctly
\(\frac{6}{25}\)
\(\frac{1}{12}\)
\(\frac{1}{3}\)
\(\frac{1}{27}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{6} \) x \( \frac{1}{9} \) = \( \frac{2 x 1}{6 x 9} \) = \( \frac{2}{54} \) = \(\frac{1}{27}\)