| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.15 |
| Score | 0% | 63% |
Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 12 small cakes per hour. The kitchen is available for 4 hours and 34 large cakes and 150 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 10 | |
| 13 | |
| 12 | |
| 7 |
If a single cook can bake 4 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 4 x 4 = 16 large cakes during that time. 34 large cakes are needed for the party so \( \frac{34}{16} \) = 2\(\frac{1}{8}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 12 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 12 x 4 = 48 small cakes during that time. 150 small cakes are needed for the party so \( \frac{150}{48} \) = 3\(\frac{1}{8}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 4 = 7 cooks.
In a class of 22 students, 11 are taking German and 5 are taking Spanish. Of the students studying German or Spanish, 5 are taking both courses. How many students are not enrolled in either course?
| 11 | |
| 13 | |
| 10 | |
| 20 |
The number of students taking German or Spanish is 11 + 5 = 16. Of that group of 16, 5 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 16 - 5 = 11 who are taking at least one language. 22 - 11 = 11 students who are not taking either language.
What is \( \sqrt{\frac{64}{9}} \)?
| 2\(\frac{2}{3}\) | |
| \(\frac{4}{7}\) | |
| 2 | |
| \(\frac{1}{2}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{64}{9}} \)
\( \frac{\sqrt{64}}{\sqrt{9}} \)
\( \frac{\sqrt{8^2}}{\sqrt{3^2}} \)
\( \frac{8}{3} \)
2\(\frac{2}{3}\)
If a car travels 15 miles in 1 hour, what is the average speed?
| 15 mph | |
| 35 mph | |
| 55 mph | |
| 25 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)If all of a roofing company's 12 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?
| 9 | |
| 5 | |
| 6 | |
| 13 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 4 crews so there are \( \frac{12}{4} \) = 3 workers on a crew. 7 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 7 x 3 = 21 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 21 - 12 = 9 new staff for the busy season.