| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.71 |
| Score | 0% | 54% |
What is \( \frac{3}{8} \) x \( \frac{1}{8} \)?
| \(\frac{3}{8}\) | |
| \(\frac{3}{64}\) | |
| \(\frac{6}{35}\) | |
| \(\frac{1}{6}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{8} \) x \( \frac{1}{8} \) = \( \frac{3 x 1}{8 x 8} \) = \( \frac{3}{64} \) = \(\frac{3}{64}\)
Cooks are needed to prepare for a large party. Each cook can bake either 5 large cakes or 12 small cakes per hour. The kitchen is available for 3 hours and 24 large cakes and 400 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 9 | |
| 7 | |
| 15 | |
| 14 |
If a single cook can bake 5 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 5 x 3 = 15 large cakes during that time. 24 large cakes are needed for the party so \( \frac{24}{15} \) = 1\(\frac{3}{5}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 12 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 12 x 3 = 36 small cakes during that time. 400 small cakes are needed for the party so \( \frac{400}{36} \) = 11\(\frac{1}{9}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 2 + 12 = 14 cooks.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 25% off." If Ezra buys two shirts, each with a regular price of $47, how much will he pay for both shirts?
| $65.80 | |
| $35.25 | |
| $82.25 | |
| $56.40 |
By buying two shirts, Ezra will save $47 x \( \frac{25}{100} \) = \( \frac{$47 x 25}{100} \) = \( \frac{$1175}{100} \) = $11.75 on the second shirt.
So, his total cost will be
$47.00 + ($47.00 - $11.75)
$47.00 + $35.25
$82.25
Solve 2 + (3 + 2) ÷ 5 x 2 - 22
| 1 | |
| 1\(\frac{1}{2}\) | |
| \(\frac{1}{3}\) | |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (3 + 2) ÷ 5 x 2 - 22
P: 2 + (5) ÷ 5 x 2 - 22
E: 2 + 5 ÷ 5 x 2 - 4
MD: 2 + \( \frac{5}{5} \) x 2 - 4
MD: 2 + \( \frac{10}{5} \) - 4
AS: \( \frac{10}{5} \) + \( \frac{10}{5} \) - 4
AS: \( \frac{20}{5} \) - 4
AS: \( \frac{20 - 20}{5} \)
\( \frac{0}{5} \)
If a rectangle is twice as long as it is wide and has a perimeter of 24 meters, what is the area of the rectangle?
| 50 m2 | |
| 8 m2 | |
| 98 m2 | |
| 32 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 24 meters so the equation becomes: 2w + 2h = 24.
Putting these two equations together and solving for width (w):
2w + 2h = 24
w + h = \( \frac{24}{2} \)
w + h = 12
w = 12 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 12 - 2w
3w = 12
w = \( \frac{12}{3} \)
w = 4
Since h = 2w that makes h = (2 x 4) = 8 and the area = h x w = 4 x 8 = 32 m2