ASVAB Arithmetic Reasoning Practice Test 128862 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

What is \( 5 \)\( \sqrt{20} \) - \( 5 \)\( \sqrt{5} \)

38% Answer Correctly
0\( \sqrt{21} \)
25\( \sqrt{5} \)
5\( \sqrt{5} \)
0\( \sqrt{4} \)

Solution

To subtract these radicals together their radicands must be the same:

5\( \sqrt{20} \) - 5\( \sqrt{5} \)
5\( \sqrt{4 \times 5} \) - 5\( \sqrt{5} \)
5\( \sqrt{2^2 \times 5} \) - 5\( \sqrt{5} \)
(5)(2)\( \sqrt{5} \) - 5\( \sqrt{5} \)
10\( \sqrt{5} \) - 5\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

10\( \sqrt{5} \) - 5\( \sqrt{5} \)
(10 - 5)\( \sqrt{5} \)
5\( \sqrt{5} \)


2

Charlie loaned Jennifer $300 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$303
$306
$318
$327

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $300
i = 0.06 x $300

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $300 + $18
total = $318


3

What is the least common multiple of 8 and 12?

72% Answer Correctly
60
20
37
24

Solution

The first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 8 and 12 have in common.


4

Which of the following statements about exponents is false?

47% Answer Correctly

b0 = 1

b1 = 1

all of these are false

b1 = b


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


5

What is c3 + 9c3?

66% Answer Correctly
8c3
-8c-3
10c3
10c9

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

1c3 + 9c3
(1 + 9)c3
10c3