| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.99 |
| Score | 0% | 60% |
What is \( \sqrt{\frac{49}{4}} \)?
| 3\(\frac{1}{2}\) | |
| 1 | |
| \(\frac{5}{7}\) | |
| 1\(\frac{1}{5}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{49}{4}} \)
\( \frac{\sqrt{49}}{\sqrt{4}} \)
\( \frac{\sqrt{7^2}}{\sqrt{2^2}} \)
\( \frac{7}{2} \)
3\(\frac{1}{2}\)
A tiger in a zoo has consumed 49 pounds of food in 7 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 70 pounds?
| 3 | |
| 2 | |
| 6 | |
| 1 |
If the tiger has consumed 49 pounds of food in 7 days that's \( \frac{49}{7} \) = 7 pounds of food per day. The tiger needs to consume 70 - 49 = 21 more pounds of food to reach 70 pounds total. At 7 pounds of food per day that's \( \frac{21}{7} \) = 3 more days.
Solve for \( \frac{6!}{2!} \)
| \( \frac{1}{1680} \) | |
| 360 | |
| 72 | |
| \( \frac{1}{504} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{6!}{2!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{6 \times 5 \times 4 \times 3}{1} \)
\( 6 \times 5 \times 4 \times 3 \)
360
What is 2\( \sqrt{2} \) x 2\( \sqrt{2} \)?
| 6 | |
| 8 | |
| 4\( \sqrt{2} \) | |
| 4\( \sqrt{4} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
2\( \sqrt{2} \) x 2\( \sqrt{2} \)
(2 x 2)\( \sqrt{2 \times 2} \)
4\( \sqrt{4} \)
Now we need to simplify the radical:
4\( \sqrt{4} \)
4\( \sqrt{2^2} \)
(4)(2)
8
What is 4b6 + 4b6?
| 8b36 | |
| 6 | |
| 8b6 | |
| 8b12 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
4b6 + 4b6
(4 + 4)b6
8b6