| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.08 |
| Score | 0% | 62% |
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 30 | |
| 31 | |
| 22 | |
| 33 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
A triathlon course includes a 200m swim, a 20.8km bike ride, and a 17.700000000000003km run. What is the total length of the race course?
| 28.4km | |
| 60.7km | |
| 38.7km | |
| 32.1km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.2km + 20.8km + 17.700000000000003km
total distance = 38.7km
Latoya scored 84% on her final exam. If each question was worth 2 points and there were 140 possible points on the exam, how many questions did Latoya answer correctly?
| 59 | |
| 65 | |
| 45 | |
| 55 |
Latoya scored 84% on the test meaning she earned 84% of the possible points on the test. There were 140 possible points on the test so she earned 140 x 0.84 = 118 points. Each question is worth 2 points so she got \( \frac{118}{2} \) = 59 questions right.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 40% larger than the original. By what percentage has the area of the logo increased?
| 25% | |
| 20% | |
| 32\(\frac{1}{2}\)% | |
| 22\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 40% the radius (and, consequently, the total area) increases by \( \frac{40\text{%}}{2} \) = 20%
Simplify \( \sqrt{50} \)
| 9\( \sqrt{4} \) | |
| 9\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{50} \)
\( \sqrt{25 \times 2} \)
\( \sqrt{5^2 \times 2} \)
5\( \sqrt{2} \)