| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.37 |
| Score | 0% | 67% |
What is (y3)5?
| 3y5 | |
| y8 | |
| y15 | |
| y2 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(y3)5What is 2c7 x 6c6?
| 12c42 | |
| 12c6 | |
| 12c13 | |
| 8c42 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
2c7 x 6c6
(2 x 6)c(7 + 6)
12c13
| 2.5 | |
| 3.0 | |
| 2.4 | |
| 1 |
1
How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 10 gallon tank to fill it exactly halfway?
| 2 | |
| 5 | |
| 2 | |
| 4 |
To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{5 \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 2
Simplify \( \frac{40}{72} \).
| \( \frac{9}{14} \) | |
| \( \frac{2}{5} \) | |
| \( \frac{5}{9} \) | |
| \( \frac{7}{19} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72]. They share 4 factors [1, 2, 4, 8] making 8 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{40}{72} \) = \( \frac{\frac{40}{8}}{\frac{72}{8}} \) = \( \frac{5}{9} \)