| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.40 |
| Score | 0% | 68% |
What is (x2)2?
| x0 | |
| 2 | |
| x4 | |
| 2x2 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x2)2A tiger in a zoo has consumed 90 pounds of food in 10 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 135 pounds?
| 1 | |
| 14 | |
| 5 | |
| 6 |
If the tiger has consumed 90 pounds of food in 10 days that's \( \frac{90}{10} \) = 9 pounds of food per day. The tiger needs to consume 135 - 90 = 45 more pounds of food to reach 135 pounds total. At 9 pounds of food per day that's \( \frac{45}{9} \) = 5 more days.
What is -2c7 - 3c7?
| c-14 | |
| -5c-7 | |
| -5c7 | |
| 5c7 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-2c7 - 3c7
(-2 - 3)c7
-5c7
What is -7z4 + 6z4?
| -z16 | |
| -z-8 | |
| -z4 | |
| -13z-4 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-7z4 + 6z4
(-7 + 6)z4
-z4
Solve for \( \frac{2!}{6!} \)
| \( \frac{1}{360} \) | |
| 1680 | |
| \( \frac{1}{20} \) | |
| \( \frac{1}{9} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)