| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 10 small cakes per hour. The kitchen is available for 2 hours and 23 large cakes and 400 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 26 | |
| 13 | |
| 14 | |
| 7 |
If a single cook can bake 2 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 2 x 2 = 4 large cakes during that time. 23 large cakes are needed for the party so \( \frac{23}{4} \) = 5\(\frac{3}{4}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 10 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 10 x 2 = 20 small cakes during that time. 400 small cakes are needed for the party so \( \frac{400}{20} \) = 20 cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 6 + 20 = 26 cooks.
What is 5z5 - 2z5?
| 7z-10 | |
| 7z25 | |
| 3z5 | |
| 3z-5 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
5z5 - 2z5
(5 - 2)z5
3z5
If a rectangle is twice as long as it is wide and has a perimeter of 6 meters, what is the area of the rectangle?
| 2 m2 | |
| 98 m2 | |
| 162 m2 | |
| 50 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 6 meters so the equation becomes: 2w + 2h = 6.
Putting these two equations together and solving for width (w):
2w + 2h = 6
w + h = \( \frac{6}{2} \)
w + h = 3
w = 3 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 3 - 2w
3w = 3
w = \( \frac{3}{3} \)
w = 1
Since h = 2w that makes h = (2 x 1) = 2 and the area = h x w = 1 x 2 = 2 m2
12 members of a bridal party need transported to a wedding reception but there are only 3 3-passenger taxis available to take them. How many will need to find other transportation?
| 7 | |
| 70 | |
| 4 | |
| 3 |
There are 3 3-passenger taxis available so that's 3 x 3 = 9 total seats. There are 12 people needing transportation leaving 12 - 9 = 3 who will have to find other transportation.
Simplify \( \sqrt{112} \)
| 2\( \sqrt{7} \) | |
| 4\( \sqrt{7} \) | |
| 5\( \sqrt{14} \) | |
| 5\( \sqrt{7} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{112} \)
\( \sqrt{16 \times 7} \)
\( \sqrt{4^2 \times 7} \)
4\( \sqrt{7} \)