| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
Charlie loaned Latoya $100 at an annual interest rate of 9%. If no payments are made, what is the total amount owed at the end of the first year?
| $105 | |
| $109 | |
| $108 | |
| $104 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $100
i = 0.09 x $100
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $100 + $9This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
PEDMAS |
|
associative |
|
commutative |
|
distributive |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
Find the average of the following numbers: 12, 6, 10, 8.
| 10 | |
| 9 | |
| 14 | |
| 7 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{12 + 6 + 10 + 8}{4} \) = \( \frac{36}{4} \) = 9
What is \( \frac{8\sqrt{27}}{4\sqrt{9}} \)?
| 3 \( \sqrt{\frac{1}{2}} \) | |
| \(\frac{1}{2}\) \( \sqrt{3} \) | |
| 2 \( \sqrt{3} \) | |
| \(\frac{1}{3}\) \( \sqrt{2} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{8\sqrt{27}}{4\sqrt{9}} \)
\( \frac{8}{4} \) \( \sqrt{\frac{27}{9}} \)
2 \( \sqrt{3} \)
If a rectangle is twice as long as it is wide and has a perimeter of 24 meters, what is the area of the rectangle?
| 32 m2 | |
| 2 m2 | |
| 98 m2 | |
| 162 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 24 meters so the equation becomes: 2w + 2h = 24.
Putting these two equations together and solving for width (w):
2w + 2h = 24
w + h = \( \frac{24}{2} \)
w + h = 12
w = 12 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 12 - 2w
3w = 12
w = \( \frac{12}{3} \)
w = 4
Since h = 2w that makes h = (2 x 4) = 8 and the area = h x w = 4 x 8 = 32 m2