ASVAB Arithmetic Reasoning Practice Test 146414 Results

Your Results Global Average
Questions 5 5
Correct 0 3.15
Score 0% 63%

Review

1

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 35% off." If Bob buys two shirts, each with a regular price of $23, how much money will he save?

70% Answer Correctly
$8.05
$11.50
$1.15
$6.90

Solution

By buying two shirts, Bob will save $23 x \( \frac{35}{100} \) = \( \frac{$23 x 35}{100} \) = \( \frac{$805}{100} \) = $8.05 on the second shirt.


2

Convert 0.0008274 to scientific notation.

62% Answer Correctly
8.274 x 10-3
8.274 x 10-4
0.827 x 10-3
8.274 x 10-5

Solution

A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

0.0008274 in scientific notation is 8.274 x 10-4


3

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

improper fraction

mixed number

fraction

integer


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


4

How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 12 gallon tank to fill it exactly halfway?

51% Answer Correctly
8
2
37
4

Solution

To fill a 12 gallon tank exactly halfway you'll need 6 gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:

cans = \( \frac{6 \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 4


5

Solve 2 + (3 + 2) ÷ 3 x 4 - 42

52% Answer Correctly
\(\frac{3}{7}\)
1\(\frac{3}{5}\)
-7\(\frac{1}{3}\)
3

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (3 + 2) ÷ 3 x 4 - 42
P: 2 + (5) ÷ 3 x 4 - 42
E: 2 + 5 ÷ 3 x 4 - 16
MD: 2 + \( \frac{5}{3} \) x 4 - 16
MD: 2 + \( \frac{20}{3} \) - 16
AS: \( \frac{6}{3} \) + \( \frac{20}{3} \) - 16
AS: \( \frac{26}{3} \) - 16
AS: \( \frac{26 - 48}{3} \)
\( \frac{-22}{3} \)
-7\(\frac{1}{3}\)