ASVAB Arithmetic Reasoning Practice Test 148622 Results

Your Results Global Average
Questions 5 5
Correct 0 3.18
Score 0% 64%

Review

1

24 members of a bridal party need transported to a wedding reception but there are only 4 5-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
3
4
1
8

Solution

There are 4 5-passenger taxis available so that's 4 x 5 = 20 total seats. There are 24 people needing transportation leaving 24 - 20 = 4 who will have to find other transportation.


2

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Damon buys two shirts, each with a regular price of $32, how much will he pay for both shirts?

57% Answer Correctly
$44.80
$43.20
$57.60
$6.40

Solution

By buying two shirts, Damon will save $32 x \( \frac{20}{100} \) = \( \frac{$32 x 20}{100} \) = \( \frac{$640}{100} \) = $6.40 on the second shirt.

So, his total cost will be
$32.00 + ($32.00 - $6.40)
$32.00 + $25.60
$57.60


3

What is \( \sqrt{\frac{64}{16}} \)?

70% Answer Correctly
2
\(\frac{3}{8}\)
1
\(\frac{6}{7}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{64}{16}} \)
\( \frac{\sqrt{64}}{\sqrt{16}} \)
\( \frac{\sqrt{8^2}}{\sqrt{4^2}} \)
\( \frac{8}{4} \)
2


4

How many 16-passenger vans will it take to drive all 51 members of the football team to an away game?

81% Answer Correctly
4 vans
8 vans
13 vans
7 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{51}{16} \) = 3\(\frac{3}{16}\)

So, it will take 3 full vans and one partially full van to transport the entire team making a total of 4 vans.


5

What is \( 9 \)\( \sqrt{32} \) + \( 2 \)\( \sqrt{2} \)

35% Answer Correctly
38\( \sqrt{2} \)
11\( \sqrt{2} \)
18\( \sqrt{32} \)
11\( \sqrt{16} \)

Solution

To add these radicals together their radicands must be the same:

9\( \sqrt{32} \) + 2\( \sqrt{2} \)
9\( \sqrt{16 \times 2} \) + 2\( \sqrt{2} \)
9\( \sqrt{4^2 \times 2} \) + 2\( \sqrt{2} \)
(9)(4)\( \sqrt{2} \) + 2\( \sqrt{2} \)
36\( \sqrt{2} \) + 2\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

36\( \sqrt{2} \) + 2\( \sqrt{2} \)
(36 + 2)\( \sqrt{2} \)
38\( \sqrt{2} \)