ASVAB Arithmetic Reasoning Practice Test 152176 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.00
Score	0%	60%

Review

Alex loaned Frank $400 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly

	$96
	$30
	$36
	$45

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $400
i = 0.09 x $400
i = $36

A tiger in a zoo has consumed 84 pounds of food in 7 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 168 pounds?

56% Answer Correctly

	14
	7
	2
	1

Solution

If the tiger has consumed 84 pounds of food in 7 days that's $ \frac{84}{7} $ = 12 pounds of food per day. The tiger needs to consume 168 - 84 = 84 more pounds of food to reach 168 pounds total. At 12 pounds of food per day that's $ \frac{84}{12} $ = 7 more days.

If $\left|a\right| = 7$, which of the following best describes a?

67% Answer Correctly

	a = 7
	a = -7
	a = 7 or a = -7
	none of these is correct

Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: $\left|-5\right| = 5$. In the case of a variable absolute value ($\left|a\right| = 5$) the value of a can be either positive or negative (a = -5 or a = 5).

What is $ 9 $$ \sqrt{75} $ + $ 2 $$ \sqrt{3} $

35% Answer Correctly

	11$ \sqrt{3} $
	18$ \sqrt{3} $
	47$ \sqrt{3} $
	11$ \sqrt{225} $

Solution

To add these radicals together their radicands must be the same:

9$ \sqrt{75} $ + 2$ \sqrt{3} $
9$ \sqrt{25 \times 3} $ + 2$ \sqrt{3} $
9$ \sqrt{5^2 \times 3} $ + 2$ \sqrt{3} $
(9)(5)$ \sqrt{3} $ + 2$ \sqrt{3} $
45$ \sqrt{3} $ + 2$ \sqrt{3} $

Now that the radicands are identical, you can add them together:

45$ \sqrt{3} $ + 2$ \sqrt{3} $
(45 + 2)$ \sqrt{3} $
47$ \sqrt{3} $

Convert b^-2 to remove the negative exponent.

68% Answer Correctly

	$ \frac{1}{b^2} $
	$ \frac{2}{b} $
	$ \frac{-1}{-2b} $
	$ \frac{-1}{b^{-2}} $

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.

	11\( \sqrt{3} \)
	18\( \sqrt{3} \)
	47\( \sqrt{3} \)
	11\( \sqrt{225} \)

	\( \frac{1}{b^2} \)
	\( \frac{2}{b} \)
	\( \frac{-1}{-2b} \)
	\( \frac{-1}{b^{-2}} \)