| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.64 |
| Score | 0% | 73% |
What is the distance in miles of a trip that takes 1 hour at an average speed of 25 miles per hour?
| 80 miles | |
| 120 miles | |
| 300 miles | |
| 25 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 25mph \times 1h \)
25 miles
What is \( \frac{27\sqrt{9}}{9\sqrt{3}} \)?
| 3 \( \sqrt{3} \) | |
| \(\frac{1}{3}\) \( \sqrt{\frac{1}{3}} \) | |
| 3 \( \sqrt{\frac{1}{3}} \) | |
| \(\frac{1}{3}\) \( \sqrt{3} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{27\sqrt{9}}{9\sqrt{3}} \)
\( \frac{27}{9} \) \( \sqrt{\frac{9}{3}} \)
3 \( \sqrt{3} \)
How many 13-passenger vans will it take to drive all 72 members of the football team to an away game?
| 7 vans | |
| 3 vans | |
| 6 vans | |
| 9 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{72}{13} \) = 5\(\frac{7}{13}\)
So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.
A triathlon course includes a 200m swim, a 20.1km bike ride, and a 7.1000000000000005km run. What is the total length of the race course?
| 55.5km | |
| 53.3km | |
| 27.4km | |
| 64.3km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.2km + 20.1km + 7.1000000000000005km
total distance = 27.4km
What is \( \frac{4}{3} \) + \( \frac{9}{7} \)?
| 1 \( \frac{1}{4} \) | |
| 2\(\frac{13}{21}\) | |
| \( \frac{3}{21} \) | |
| 2 \( \frac{4}{7} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 7}{3 x 7} \) + \( \frac{9 x 3}{7 x 3} \)
\( \frac{28}{21} \) + \( \frac{27}{21} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{28 + 27}{21} \) = \( \frac{55}{21} \) = 2\(\frac{13}{21}\)