| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
What is \( \frac{3}{9} \) ÷ \( \frac{1}{5} \)?
| \(\frac{1}{24}\) | |
| \(\frac{4}{21}\) | |
| 1\(\frac{2}{3}\) | |
| \(\frac{8}{45}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{3}{9} \) ÷ \( \frac{1}{5} \) = \( \frac{3}{9} \) x \( \frac{5}{1} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{9} \) x \( \frac{5}{1} \) = \( \frac{3 x 5}{9 x 1} \) = \( \frac{15}{9} \) = 1\(\frac{2}{3}\)
Solve for \( \frac{3!}{6!} \)
| \( \frac{1}{504} \) | |
| \( \frac{1}{120} \) | |
| \( \frac{1}{4} \) | |
| 72 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{6!} \)
\( \frac{3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4} \)
\( \frac{1}{120} \)
What is the distance in miles of a trip that takes 9 hours at an average speed of 35 miles per hour?
| 315 miles | |
| 200 miles | |
| 360 miles | |
| 60 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 35mph \times 9h \)
315 miles
What is -8y3 + 9y3?
| 17y3 | |
| y6 | |
| y3 | |
| y9 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-8y3 + 9y3
(-8 + 9)y3
y3
If a rectangle is twice as long as it is wide and has a perimeter of 42 meters, what is the area of the rectangle?
| 32 m2 | |
| 18 m2 | |
| 162 m2 | |
| 98 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 42 meters so the equation becomes: 2w + 2h = 42.
Putting these two equations together and solving for width (w):
2w + 2h = 42
w + h = \( \frac{42}{2} \)
w + h = 21
w = 21 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 21 - 2w
3w = 21
w = \( \frac{21}{3} \)
w = 7
Since h = 2w that makes h = (2 x 7) = 14 and the area = h x w = 7 x 14 = 98 m2