| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
12 members of a bridal party need transported to a wedding reception but there are only 2 5-passenger taxis available to take them. How many will need to find other transportation?
| 9 | |
| 3 | |
| 2 | |
| 6 |
There are 2 5-passenger taxis available so that's 2 x 5 = 10 total seats. There are 12 people needing transportation leaving 12 - 10 = 2 who will have to find other transportation.
If \( \left|y - 7\right| \) - 4 = -5, which of these is a possible value for y?
| 8 | |
| 7 | |
| 11 | |
| -4 |
First, solve for \( \left|y - 7\right| \):
\( \left|y - 7\right| \) - 4 = -5
\( \left|y - 7\right| \) = -5 + 4
\( \left|y - 7\right| \) = -1
The value inside the absolute value brackets can be either positive or negative so (y - 7) must equal - 1 or --1 for \( \left|y - 7\right| \) to equal -1:
| y - 7 = -1 y = -1 + 7 y = 6 | y - 7 = 1 y = 1 + 7 y = 8 |
So, y = 8 or y = 6.
Simplify \( \sqrt{125} \)
| 7\( \sqrt{5} \) | |
| 5\( \sqrt{5} \) | |
| 4\( \sqrt{5} \) | |
| 6\( \sqrt{10} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{125} \)
\( \sqrt{25 \times 5} \)
\( \sqrt{5^2 \times 5} \)
5\( \sqrt{5} \)
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 7 to 2 and the ratio of baseball to basketball cards is 7 to 1, what is the ratio of football to basketball cards?
| 49:2 | |
| 7:6 | |
| 3:4 | |
| 9:4 |
The ratio of football cards to baseball cards is 7:2 and the ratio of baseball cards to basketball cards is 7:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 49:14 and the ratio of baseball cards to basketball cards as 14:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 49:14, 14:2 which reduces to 49:2.
What is \( \frac{-2x^8}{2x^3} \)?
| -x5 | |
| -x2\(\frac{2}{3}\) | |
| -x11 | |
| -x\(\frac{3}{8}\) |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-2x^8}{2x^3} \)
\( \frac{-2}{2} \) x(8 - 3)
-x5