ASVAB Arithmetic Reasoning Practice Test 159223 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

What is \( \frac{3}{7} \) x \( \frac{2}{8} \)?

72% Answer Correctly
\(\frac{4}{35}\)
\(\frac{12}{25}\)
\(\frac{3}{28}\)
\(\frac{1}{63}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{7} \) x \( \frac{2}{8} \) = \( \frac{3 x 2}{7 x 8} \) = \( \frac{6}{56} \) = \(\frac{3}{28}\)


2

What is (c3)2?

79% Answer Correctly
c
c-1
c6
c5

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(c3)2
c(3 * 2)
c6


3

What is \( 2 \)\( \sqrt{50} \) - \( 3 \)\( \sqrt{2} \)

38% Answer Correctly
6\( \sqrt{50} \)
6\( \sqrt{2} \)
7\( \sqrt{2} \)
-1\( \sqrt{50} \)

Solution

To subtract these radicals together their radicands must be the same:

2\( \sqrt{50} \) - 3\( \sqrt{2} \)
2\( \sqrt{25 \times 2} \) - 3\( \sqrt{2} \)
2\( \sqrt{5^2 \times 2} \) - 3\( \sqrt{2} \)
(2)(5)\( \sqrt{2} \) - 3\( \sqrt{2} \)
10\( \sqrt{2} \) - 3\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

10\( \sqrt{2} \) - 3\( \sqrt{2} \)
(10 - 3)\( \sqrt{2} \)
7\( \sqrt{2} \)


4

The total water usage for a city is 45,000 gallons each day. Of that total, 14% is for personal use and 29% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
4,200
6,750
7,000
7,350

Solution

29% of the water consumption is industrial use and 14% is personal use so (29% - 14%) = 15% more water is used for industrial purposes. 45,000 gallons are consumed daily so industry consumes \( \frac{15}{100} \) x 45,000 gallons = 6,750 gallons.


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

commutative property for multiplication

distributive property for division

distributive property for multiplication

commutative property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).