| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.05 |
| Score | 0% | 61% |
What is \( \frac{3}{7} \) x \( \frac{2}{8} \)?
| \(\frac{4}{35}\) | |
| \(\frac{12}{25}\) | |
| \(\frac{3}{28}\) | |
| \(\frac{1}{63}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{7} \) x \( \frac{2}{8} \) = \( \frac{3 x 2}{7 x 8} \) = \( \frac{6}{56} \) = \(\frac{3}{28}\)
What is (c3)2?
| c | |
| c-1 | |
| c6 | |
| c5 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(c3)2What is \( 2 \)\( \sqrt{50} \) - \( 3 \)\( \sqrt{2} \)
| 6\( \sqrt{50} \) | |
| 6\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| -1\( \sqrt{50} \) |
To subtract these radicals together their radicands must be the same:
2\( \sqrt{50} \) - 3\( \sqrt{2} \)
2\( \sqrt{25 \times 2} \) - 3\( \sqrt{2} \)
2\( \sqrt{5^2 \times 2} \) - 3\( \sqrt{2} \)
(2)(5)\( \sqrt{2} \) - 3\( \sqrt{2} \)
10\( \sqrt{2} \) - 3\( \sqrt{2} \)
Now that the radicands are identical, you can subtract them:
10\( \sqrt{2} \) - 3\( \sqrt{2} \)The total water usage for a city is 45,000 gallons each day. Of that total, 14% is for personal use and 29% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 4,200 | |
| 6,750 | |
| 7,000 | |
| 7,350 |
29% of the water consumption is industrial use and 14% is personal use so (29% - 14%) = 15% more water is used for industrial purposes. 45,000 gallons are consumed daily so industry consumes \( \frac{15}{100} \) x 45,000 gallons = 6,750 gallons.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
|
distributive property for division |
|
distributive property for multiplication |
|
commutative property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).