| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.29 |
| Score | 0% | 66% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 10% off." If Frank buys two shirts, each with a regular price of $13, how much will he pay for both shirts?
| $14.30 | |
| $24.70 | |
| $1.30 | |
| $11.70 |
By buying two shirts, Frank will save $13 x \( \frac{10}{100} \) = \( \frac{$13 x 10}{100} \) = \( \frac{$130}{100} \) = $1.30 on the second shirt.
So, his total cost will be
$13.00 + ($13.00 - $1.30)
$13.00 + $11.70
$24.70
If \(\left|a\right| = 7\), which of the following best describes a?
a = 7 or a = -7 |
|
none of these is correct |
|
a = -7 |
|
a = 7 |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
Simplify \( \frac{40}{60} \).
| \( \frac{2}{5} \) | |
| \( \frac{2}{3} \) | |
| \( \frac{4}{11} \) | |
| \( \frac{5}{12} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 6 factors [1, 2, 4, 5, 10, 20] making 20 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{40}{60} \) = \( \frac{\frac{40}{20}}{\frac{60}{20}} \) = \( \frac{2}{3} \)
What is the distance in miles of a trip that takes 5 hours at an average speed of 45 miles per hour?
| 130 miles | |
| 225 miles | |
| 150 miles | |
| 245 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 45mph \times 5h \)
225 miles
Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 20 small cakes per hour. The kitchen is available for 4 hours and 35 large cakes and 400 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 10 | |
| 5 | |
| 8 | |
| 7 |
If a single cook can bake 4 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 4 x 4 = 16 large cakes during that time. 35 large cakes are needed for the party so \( \frac{35}{16} \) = 2\(\frac{3}{16}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 20 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 20 x 4 = 80 small cakes during that time. 400 small cakes are needed for the party so \( \frac{400}{80} \) = 5 cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 5 = 8 cooks.