| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.13 |
| Score | 0% | 63% |
If all of a roofing company's 20 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 9 complete crews out on jobs?
| 13 | |
| 4 | |
| 16 | |
| 10 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 20 workers at the company now and that's enough to staff 5 crews so there are \( \frac{20}{5} \) = 4 workers on a crew. 9 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 9 x 4 = 36 total workers to staff the crews during the busy season. The company already employs 20 workers so they need to add 36 - 20 = 16 new staff for the busy season.
A triathlon course includes a 400m swim, a 40.5km bike ride, and a 8.9km run. What is the total length of the race course?
| 32.9km | |
| 32.5km | |
| 49.8km | |
| 42.8km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 400 meters to kilometers, divide the distance by 1000 to get 0.4km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.4km + 40.5km + 8.9km
total distance = 49.8km
On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 30 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 29 | |
| 38 | |
| 35 | |
| 50 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{50}{100} \) = \( \frac{50 x 30}{100} \) = \( \frac{1500}{100} \) = 15 shots
The center makes 40% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{15}{\frac{40}{100}} \) = 15 x \( \frac{100}{40} \) = \( \frac{15 x 100}{40} \) = \( \frac{1500}{40} \) = 38 shots
to make the same number of shots as the guard and thus score the same number of points.
9 members of a bridal party need transported to a wedding reception but there are only 2 3-passenger taxis available to take them. How many will need to find other transportation?
| 7 | |
| 3 | |
| 2 | |
| 5 |
There are 2 3-passenger taxis available so that's 2 x 3 = 6 total seats. There are 9 people needing transportation leaving 9 - 6 = 3 who will have to find other transportation.
What is \( \frac{4\sqrt{20}}{2\sqrt{4}} \)?
| \(\frac{1}{2}\) \( \sqrt{5} \) | |
| \(\frac{1}{5}\) \( \sqrt{\frac{1}{2}} \) | |
| 2 \( \sqrt{5} \) | |
| \(\frac{1}{5}\) \( \sqrt{2} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{4\sqrt{20}}{2\sqrt{4}} \)
\( \frac{4}{2} \) \( \sqrt{\frac{20}{4}} \)
2 \( \sqrt{5} \)