The amount of flour you need is (2\(\frac{1}{4}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{18}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{14}{8} \) cups
1\(\frac{3}{4}\) cups

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{39}{7} \) = 5\(\frac{4}{7}\)

So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (3 + 2) ÷ 5 x 3 - 2²
P: 3 + (5) ÷ 5 x 3 - 2²
E: 3 + 5 ÷ 5 x 3 - 4
MD: 3 + \( \frac{5}{5} \) x 3 - 4
MD: 3 + \( \frac{15}{5} \) - 4
AS: \( \frac{15}{5} \) + \( \frac{15}{5} \) - 4
AS: \( \frac{30}{5} \) - 4
AS: \( \frac{30 - 20}{5} \)
\( \frac{10}{5} \)
2

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-y^6}{3y^3} \)
\( \frac{-1}{3} \) y^{(6 - 3)}
-\(\frac{1}{3}\)y³

There are 3 3-passenger taxis available so that's 3 x 3 = 9 total seats. There are 12 people needing transportation leaving 12 - 9 = 3 who will have to find other transportation.