| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.86 |
| Score | 0% | 57% |
Diane scored 79% on her final exam. If each question was worth 3 points and there were 270 possible points on the exam, how many questions did Diane answer correctly?
| 71 | |
| 75 | |
| 69 | |
| 63 |
Diane scored 79% on the test meaning she earned 79% of the possible points on the test. There were 270 possible points on the test so she earned 270 x 0.79 = 213 points. Each question is worth 3 points so she got \( \frac{213}{3} \) = 71 questions right.
The total water usage for a city is 40,000 gallons each day. Of that total, 35% is for personal use and 52% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 6,800 | |
| 6,500 | |
| 4,800 | |
| 11,900 |
52% of the water consumption is industrial use and 35% is personal use so (52% - 35%) = 17% more water is used for industrial purposes. 40,000 gallons are consumed daily so industry consumes \( \frac{17}{100} \) x 40,000 gallons = 6,800 gallons.
If there were a total of 50 raffle tickets sold and you bought 3 tickets, what's the probability that you'll win the raffle?
| 9% | |
| 7% | |
| 11% | |
| 1% |
You have 3 out of the total of 50 raffle tickets sold so you have a (\( \frac{3}{50} \)) x 100 = \( \frac{3 \times 100}{50} \) = \( \frac{300}{50} \) = 7% chance to win the raffle.
What is \( \sqrt{\frac{81}{16}} \)?
| \(\frac{4}{7}\) | |
| \(\frac{1}{3}\) | |
| 2\(\frac{1}{4}\) | |
| \(\frac{3}{5}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{81}{16}} \)
\( \frac{\sqrt{81}}{\sqrt{16}} \)
\( \frac{\sqrt{9^2}}{\sqrt{4^2}} \)
\( \frac{9}{4} \)
2\(\frac{1}{4}\)
What is 6\( \sqrt{9} \) x 3\( \sqrt{7} \)?
| 9\( \sqrt{9} \) | |
| 9\( \sqrt{7} \) | |
| 54\( \sqrt{7} \) | |
| 9\( \sqrt{63} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
6\( \sqrt{9} \) x 3\( \sqrt{7} \)
(6 x 3)\( \sqrt{9 \times 7} \)
18\( \sqrt{63} \)
Now we need to simplify the radical:
18\( \sqrt{63} \)
18\( \sqrt{7 \times 9} \)
18\( \sqrt{7 \times 3^2} \)
(18)(3)\( \sqrt{7} \)
54\( \sqrt{7} \)