ASVAB Arithmetic Reasoning Practice Test 162707 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

What is the least common multiple of 3 and 11?

72% Answer Correctly
10
2
33
12

Solution

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 have in common.


2

What is 6c5 + 7c5?

66% Answer Correctly
c-5
13c5
-c5
c5

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

6c5 + 7c5
(6 + 7)c5
13c5


3

A machine in a factory has an error rate of 8 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 2 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
121.4
165.9
117.6
98.7

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{8}{100} \) x 6 = \( \frac{8 \times 6}{100} \) = \( \frac{48}{100} \) = 0.48 errors per hour

So, in an average hour, the machine will produce 6 - 0.48 = 5.52 error free parts.

The machine ran for 24 - 2 = 22 hours yesterday so you would expect that 22 x 5.52 = 121.4 error free parts were produced yesterday.


4

Alex loaned Bob $400 at an annual interest rate of 7%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$56
$28
$99
$45

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $400
i = 0.07 x $400
i = $28


5

What is \( \frac{9}{2} \) - \( \frac{6}{8} \)?

61% Answer Correctly
2 \( \frac{1}{8} \)
\( \frac{1}{9} \)
3\(\frac{3}{4}\)
2 \( \frac{1}{9} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 2 and 8 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{9 x 4}{2 x 4} \) - \( \frac{6 x 1}{8 x 1} \)

\( \frac{36}{8} \) - \( \frac{6}{8} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{36 - 6}{8} \) = \( \frac{30}{8} \) = 3\(\frac{3}{4}\)