ASVAB Arithmetic Reasoning Practice Test 166280 Results

Your Results Global Average
Questions 5 5
Correct 0 3.18
Score 0% 64%

Review

1

Which of the following is an improper fraction?

70% Answer Correctly

\({7 \over 5} \)

\({a \over 5} \)

\({2 \over 5} \)

\(1 {2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

A bread recipe calls for 2\(\frac{3}{8}\) cups of flour. If you only have 1\(\frac{1}{2}\) cups, how much more flour is needed?

62% Answer Correctly
\(\frac{7}{8}\) cups
1 cups
2 cups
\(\frac{3}{4}\) cups

Solution

The amount of flour you need is (2\(\frac{3}{8}\) - 1\(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{19}{8} \) - \( \frac{12}{8} \)) cups
\( \frac{7}{8} \) cups
\(\frac{7}{8}\) cups


3

A tiger in a zoo has consumed 90 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 120 pounds?

56% Answer Correctly
5
10
3
7

Solution

If the tiger has consumed 90 pounds of food in 9 days that's \( \frac{90}{9} \) = 10 pounds of food per day. The tiger needs to consume 120 - 90 = 30 more pounds of food to reach 120 pounds total. At 10 pounds of food per day that's \( \frac{30}{10} \) = 3 more days.


4

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

greatest common factor

least common multiple

absolute value

least common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


5

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

distributive property for division

distributive property for multiplication

commutative property for multiplication

commutative property for division


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.