| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.25 |
| Score | 0% | 65% |
Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 19 small cakes per hour. The kitchen is available for 4 hours and 36 large cakes and 300 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 7 | |
| 9 | |
| 12 | |
| 14 |
If a single cook can bake 4 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 4 x 4 = 16 large cakes during that time. 36 large cakes are needed for the party so \( \frac{36}{16} \) = 2\(\frac{1}{4}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 19 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 19 x 4 = 76 small cakes during that time. 300 small cakes are needed for the party so \( \frac{300}{76} \) = 3\(\frac{18}{19}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 4 = 7 cooks.
If the ratio of home fans to visiting fans in a crowd is 3:1 and all 44,000 seats in a stadium are filled, how many home fans are in attendance?
| 36,000 | |
| 30,667 | |
| 24,000 | |
| 33,000 |
A ratio of 3:1 means that there are 3 home fans for every one visiting fan. So, of every 4 fans, 3 are home fans and \( \frac{3}{4} \) of every fan in the stadium is a home fan:
44,000 fans x \( \frac{3}{4} \) = \( \frac{132000}{4} \) = 33,000 fans.
What is the greatest common factor of 64 and 32?
| 25 | |
| 26 | |
| 22 | |
| 32 |
The factors of 64 are [1, 2, 4, 8, 16, 32, 64] and the factors of 32 are [1, 2, 4, 8, 16, 32]. They share 6 factors [1, 2, 4, 8, 16, 32] making 32 the greatest factor 64 and 32 have in common.
4! = ?
4 x 3 |
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3 x 2 x 1 |
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5 x 4 x 3 x 2 x 1 |
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4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
Which of the following is an improper fraction?
\({2 \over 5} \) |
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\({a \over 5} \) |
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\({7 \over 5} \) |
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\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.