| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.05 |
| Score | 0% | 61% |
What is (a5)4?
| 4a5 | |
| a-1 | |
| 5a4 | |
| a20 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(a5)4If a rectangle is twice as long as it is wide and has a perimeter of 54 meters, what is the area of the rectangle?
| 162 m2 | |
| 98 m2 | |
| 128 m2 | |
| 32 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.
Putting these two equations together and solving for width (w):
2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9
Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m2
What is \( 9 \)\( \sqrt{80} \) - \( 6 \)\( \sqrt{5} \)
| 54\( \sqrt{5} \) | |
| 30\( \sqrt{5} \) | |
| 54\( \sqrt{400} \) | |
| 3\( \sqrt{5} \) |
To subtract these radicals together their radicands must be the same:
9\( \sqrt{80} \) - 6\( \sqrt{5} \)
9\( \sqrt{16 \times 5} \) - 6\( \sqrt{5} \)
9\( \sqrt{4^2 \times 5} \) - 6\( \sqrt{5} \)
(9)(4)\( \sqrt{5} \) - 6\( \sqrt{5} \)
36\( \sqrt{5} \) - 6\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
36\( \sqrt{5} \) - 6\( \sqrt{5} \)What is \( \frac{2}{9} \) ÷ \( \frac{2}{6} \)?
| \(\frac{12}{49}\) | |
| \(\frac{2}{21}\) | |
| \(\frac{3}{20}\) | |
| \(\frac{2}{3}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{9} \) ÷ \( \frac{2}{6} \) = \( \frac{2}{9} \) x \( \frac{6}{2} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{9} \) x \( \frac{6}{2} \) = \( \frac{2 x 6}{9 x 2} \) = \( \frac{12}{18} \) = \(\frac{2}{3}\)
Charlie loaned April $300 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?
| $315 | |
| $321 | |
| $309 | |
| $318 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $300
i = 0.03 x $300
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $300 + $9