ASVAB Arithmetic Reasoning Practice Test 168943 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

What is (a5)4?

80% Answer Correctly
4a5
a-1
5a4
a20

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(a5)4
a(5 * 4)
a20


2

If a rectangle is twice as long as it is wide and has a perimeter of 54 meters, what is the area of the rectangle?

47% Answer Correctly
162 m2
98 m2
128 m2
32 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.

Putting these two equations together and solving for width (w):

2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9

Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m2


3

What is \( 9 \)\( \sqrt{80} \) - \( 6 \)\( \sqrt{5} \)

39% Answer Correctly
54\( \sqrt{5} \)
30\( \sqrt{5} \)
54\( \sqrt{400} \)
3\( \sqrt{5} \)

Solution

To subtract these radicals together their radicands must be the same:

9\( \sqrt{80} \) - 6\( \sqrt{5} \)
9\( \sqrt{16 \times 5} \) - 6\( \sqrt{5} \)
9\( \sqrt{4^2 \times 5} \) - 6\( \sqrt{5} \)
(9)(4)\( \sqrt{5} \) - 6\( \sqrt{5} \)
36\( \sqrt{5} \) - 6\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

36\( \sqrt{5} \) - 6\( \sqrt{5} \)
(36 - 6)\( \sqrt{5} \)
30\( \sqrt{5} \)


4

What is \( \frac{2}{9} \) ÷ \( \frac{2}{6} \)?

68% Answer Correctly
\(\frac{12}{49}\)
\(\frac{2}{21}\)
\(\frac{3}{20}\)
\(\frac{2}{3}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{2}{9} \) ÷ \( \frac{2}{6} \) = \( \frac{2}{9} \) x \( \frac{6}{2} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{9} \) x \( \frac{6}{2} \) = \( \frac{2 x 6}{9 x 2} \) = \( \frac{12}{18} \) = \(\frac{2}{3}\)


5

Charlie loaned April $300 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$315
$321
$309
$318

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $300
i = 0.03 x $300

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $300 + $9
total = $309