| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.33 |
| Score | 0% | 67% |
What is the next number in this sequence: 1, 7, 13, 19, 25, __________ ?
| 33 | |
| 23 | |
| 35 | |
| 31 |
The equation for this sequence is:
an = an-1 + 6
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 6
a6 = 25 + 6
a6 = 31
Which of the following statements about exponents is false?
b0 = 1 |
|
b1 = b |
|
b1 = 1 |
|
all of these are false |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
What is \( \frac{2}{8} \) ÷ \( \frac{3}{5} \)?
| \(\frac{5}{12}\) | |
| \(\frac{4}{63}\) | |
| \(\frac{3}{10}\) | |
| \(\frac{2}{35}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{8} \) ÷ \( \frac{3}{5} \) = \( \frac{2}{8} \) x \( \frac{5}{3} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{8} \) x \( \frac{5}{3} \) = \( \frac{2 x 5}{8 x 3} \) = \( \frac{10}{24} \) = \(\frac{5}{12}\)
In a class of 29 students, 15 are taking German and 13 are taking Spanish. Of the students studying German or Spanish, 6 are taking both courses. How many students are not enrolled in either course?
| 7 | |
| 23 | |
| 24 | |
| 15 |
The number of students taking German or Spanish is 15 + 13 = 28. Of that group of 28, 6 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 28 - 6 = 22 who are taking at least one language. 29 - 22 = 7 students who are not taking either language.
Solve for \( \frac{4!}{2!} \)
| \( \frac{1}{42} \) | |
| 20 | |
| 12 | |
| 5 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{2!} \)
\( \frac{4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{4 \times 3}{1} \)
\( 4 \times 3 \)
12