ASVAB Arithmetic Reasoning Practice Test 168983 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

What is the next number in this sequence: 1, 7, 13, 19, 25, __________ ?

92% Answer Correctly
33
23
35
31

Solution

The equation for this sequence is:

an = an-1 + 6

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 6
a6 = 25 + 6
a6 = 31


2

Which of the following statements about exponents is false?

47% Answer Correctly

b0 = 1

b1 = b

b1 = 1

all of these are false


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


3

What is \( \frac{2}{8} \) ÷ \( \frac{3}{5} \)?

68% Answer Correctly
\(\frac{5}{12}\)
\(\frac{4}{63}\)
\(\frac{3}{10}\)
\(\frac{2}{35}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{2}{8} \) ÷ \( \frac{3}{5} \) = \( \frac{2}{8} \) x \( \frac{5}{3} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{8} \) x \( \frac{5}{3} \) = \( \frac{2 x 5}{8 x 3} \) = \( \frac{10}{24} \) = \(\frac{5}{12}\)


4

In a class of 29 students, 15 are taking German and 13 are taking Spanish. Of the students studying German or Spanish, 6 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
7
23
24
15

Solution

The number of students taking German or Spanish is 15 + 13 = 28. Of that group of 28, 6 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 28 - 6 = 22 who are taking at least one language. 29 - 22 = 7 students who are not taking either language.


5

Solve for \( \frac{4!}{2!} \)

67% Answer Correctly
\( \frac{1}{42} \)
20
12
5

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{4!}{2!} \)
\( \frac{4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{4 \times 3}{1} \)
\( 4 \times 3 \)
12