ASVAB Arithmetic Reasoning Practice Test 16990 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.36
Score	0%	67%

Review

What is $ 6 $$ \sqrt{75} $ - $ 5 $$ \sqrt{3} $

38% Answer Correctly

	30$ \sqrt{225} $
	25$ \sqrt{3} $
	$ \sqrt{225} $
	$ \sqrt{-16} $

Solution

To subtract these radicals together their radicands must be the same:

6$ \sqrt{75} $ - 5$ \sqrt{3} $
6$ \sqrt{25 \times 3} $ - 5$ \sqrt{3} $
6$ \sqrt{5^2 \times 3} $ - 5$ \sqrt{3} $
(6)(5)$ \sqrt{3} $ - 5$ \sqrt{3} $
30$ \sqrt{3} $ - 5$ \sqrt{3} $

Now that the radicands are identical, you can subtract them:

30$ \sqrt{3} $ - 5$ \sqrt{3} $
(30 - 5)$ \sqrt{3} $
25$ \sqrt{3} $

If a car travels 140 miles in 4 hours, what is the average speed?

86% Answer Correctly

	15 mph
	70 mph
	35 mph
	40 mph

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = $ \frac{\text{distance}}{\text{time}} $
speed = $ \frac{140mi}{4h} $
35 mph

Charlie loaned Christine $1,000 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly

	$1,090
	$1,030
	$1,020
	$1,060

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $1,000
i = 0.06 x $1,000

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,000 + $60
total = $1,060

Which of the following is not an integer?

77% Answer Correctly

	0
	1
	${1 \over 2}$
	-1

Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.

If $ \left|c - 3\right| $ + 5 = -7, which of these is a possible value for c?

62% Answer Correctly

	-4
	12
	-9
	2

Solution

First, solve for $ \left|c - 3\right| $:

The value inside the absolute value brackets can be either positive or negative so (c - 3) must equal - 12 or --12 for $ \left|c - 3\right| $ to equal -12:

c - 3 = -12
c = -12 + 3
c = -9

c - 3 = 12
c = 12 + 3
c = 15

So, c = 15 or c = -9.

	30\( \sqrt{225} \)
	25\( \sqrt{3} \)
	\( \sqrt{225} \)
	\( \sqrt{-16} \)

	0
	1
	\({1 \over 2}\)
	-1