| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.73 |
| Score | 0% | 55% |
How many 2 gallon cans worth of fuel would you need to pour into an empty 16 gallon tank to fill it exactly halfway?
| 8 | |
| 4 | |
| 2 | |
| 5 |
To fill a 16 gallon tank exactly halfway you'll need 8 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{8 \text{ gallons}}{2 \text{ gallons}} \) = 4
A triathlon course includes a 300m swim, a 20.8km bike ride, and a 6.0km run. What is the total length of the race course?
| 39.4km | |
| 27.1km | |
| 46.9km | |
| 36.4km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 300 meters to kilometers, divide the distance by 1000 to get 0.3km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.3km + 20.8km + 6.0km
total distance = 27.1km
Ezra loaned Latoya $700 at an annual interest rate of 4%. If no payments are made, what is the total amount owed at the end of the first year?
| $735 | |
| $728 | |
| $756 | |
| $721 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $700
i = 0.04 x $700
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $700 + $28What is \( 7 \)\( \sqrt{45} \) + \( 6 \)\( \sqrt{5} \)
| 13\( \sqrt{9} \) | |
| 42\( \sqrt{45} \) | |
| 42\( \sqrt{9} \) | |
| 27\( \sqrt{5} \) |
To add these radicals together their radicands must be the same:
7\( \sqrt{45} \) + 6\( \sqrt{5} \)
7\( \sqrt{9 \times 5} \) + 6\( \sqrt{5} \)
7\( \sqrt{3^2 \times 5} \) + 6\( \sqrt{5} \)
(7)(3)\( \sqrt{5} \) + 6\( \sqrt{5} \)
21\( \sqrt{5} \) + 6\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
21\( \sqrt{5} \) + 6\( \sqrt{5} \)If a rectangle is twice as long as it is wide and has a perimeter of 12 meters, what is the area of the rectangle?
| 32 m2 | |
| 128 m2 | |
| 8 m2 | |
| 72 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 12 meters so the equation becomes: 2w + 2h = 12.
Putting these two equations together and solving for width (w):
2w + 2h = 12
w + h = \( \frac{12}{2} \)
w + h = 6
w = 6 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 6 - 2w
3w = 6
w = \( \frac{6}{3} \)
w = 2
Since h = 2w that makes h = (2 x 2) = 4 and the area = h x w = 2 x 4 = 8 m2