ASVAB Arithmetic Reasoning Practice Test 170542 Results

Your Results Global Average
Questions 5 5
Correct 0 2.73
Score 0% 55%

Review

1

How many 2 gallon cans worth of fuel would you need to pour into an empty 16 gallon tank to fill it exactly halfway?

51% Answer Correctly
8
4
2
5

Solution

To fill a 16 gallon tank exactly halfway you'll need 8 gallons of fuel. Each fuel can holds 2 gallons so:

cans = \( \frac{8 \text{ gallons}}{2 \text{ gallons}} \) = 4


2

A triathlon course includes a 300m swim, a 20.8km bike ride, and a 6.0km run. What is the total length of the race course?

69% Answer Correctly
39.4km
27.1km
46.9km
36.4km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 300 meters to kilometers, divide the distance by 1000 to get 0.3km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.3km + 20.8km + 6.0km
total distance = 27.1km


3

Ezra loaned Latoya $700 at an annual interest rate of 4%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$735
$728
$756
$721

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $700
i = 0.04 x $700

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $700 + $28
total = $728


4

What is \( 7 \)\( \sqrt{45} \) + \( 6 \)\( \sqrt{5} \)

35% Answer Correctly
13\( \sqrt{9} \)
42\( \sqrt{45} \)
42\( \sqrt{9} \)
27\( \sqrt{5} \)

Solution

To add these radicals together their radicands must be the same:

7\( \sqrt{45} \) + 6\( \sqrt{5} \)
7\( \sqrt{9 \times 5} \) + 6\( \sqrt{5} \)
7\( \sqrt{3^2 \times 5} \) + 6\( \sqrt{5} \)
(7)(3)\( \sqrt{5} \) + 6\( \sqrt{5} \)
21\( \sqrt{5} \) + 6\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

21\( \sqrt{5} \) + 6\( \sqrt{5} \)
(21 + 6)\( \sqrt{5} \)
27\( \sqrt{5} \)


5

If a rectangle is twice as long as it is wide and has a perimeter of 12 meters, what is the area of the rectangle?

47% Answer Correctly
32 m2
128 m2
8 m2
72 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 12 meters so the equation becomes: 2w + 2h = 12.

Putting these two equations together and solving for width (w):

2w + 2h = 12
w + h = \( \frac{12}{2} \)
w + h = 6
w = 6 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 6 - 2w
3w = 6
w = \( \frac{6}{3} \)
w = 2

Since h = 2w that makes h = (2 x 2) = 4 and the area = h x w = 2 x 4 = 8 m2