ASVAB Arithmetic Reasoning Practice Test 172140 Results

Your Results Global Average
Questions 5 5
Correct 0 3.93
Score 0% 79%

Review

1

How many hours does it take a car to travel 50 miles at an average speed of 25 miles per hour?

86% Answer Correctly
5 hours
3 hours
9 hours
2 hours

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for time:

time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{50mi}{25mph} \)
2 hours


2

Convert 4,023,000 to scientific notation.

62% Answer Correctly
40.23 x 105
0.402 x 107
4.023 x 10-6
4.023 x 106

Solution

A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

4,023,000 in scientific notation is 4.023 x 106


3

If a car travels 180 miles in 3 hours, what is the average speed?

86% Answer Correctly
55 mph
45 mph
20 mph
60 mph

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)
speed = \( \frac{180mi}{3h} \)
60 mph


4

What is the next number in this sequence: 1, 7, 13, 19, 25, __________ ?

92% Answer Correctly
33
31
30
34

Solution

The equation for this sequence is:

an = an-1 + 6

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 6
a6 = 25 + 6
a6 = 31


5

Convert c-2 to remove the negative exponent.

68% Answer Correctly
\( \frac{1}{c^2} \)
\( \frac{-2}{c} \)
\( \frac{-1}{-2c^{2}} \)
\( \frac{-2}{-c} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.