| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.39 |
| Score | 0% | 68% |
4! = ?
3 x 2 x 1 |
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4 x 3 x 2 x 1 |
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5 x 4 x 3 x 2 x 1 |
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4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
What is 4c5 - 8c5?
| -4c-5 | |
| 12c5 | |
| -4c5 | |
| 12c-10 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
4c5 - 8c5
(4 - 8)c5
-4c5
17 members of a bridal party need transported to a wedding reception but there are only 3 5-passenger taxis available to take them. How many will need to find other transportation?
| 2 | |
| 5 | |
| 7 | |
| 4 |
There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 17 people needing transportation leaving 17 - 15 = 2 who will have to find other transportation.
The __________ is the smallest positive integer that is a multiple of two or more integers.
absolute value |
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least common multiple |
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least common factor |
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greatest common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
If all of a roofing company's 16 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 16 | |
| 14 | |
| 17 | |
| 1 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 16 workers at the company now and that's enough to staff 4 crews so there are \( \frac{16}{4} \) = 4 workers on a crew. 8 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 8 x 4 = 32 total workers to staff the crews during the busy season. The company already employs 16 workers so they need to add 32 - 16 = 16 new staff for the busy season.