To add these radicals together their radicands must be the same:

6\( \sqrt{28} \) + 2\( \sqrt{7} \)
6\( \sqrt{4 \times 7} \) + 2\( \sqrt{7} \)
6\( \sqrt{2^2 \times 7} \) + 2\( \sqrt{7} \)
(6)(2)\( \sqrt{7} \) + 2\( \sqrt{7} \)
12\( \sqrt{7} \) + 2\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

12\( \sqrt{7} \) + 2\( \sqrt{7} \)
(12 + 2)\( \sqrt{7} \)
14\( \sqrt{7} \)

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,500
i = 0.03 x $1,500

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,500 + $45
total = $1,545

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [10, 20, 30, 40, 50] making 10 the smallest multiple 2 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{9 x 5}{2 x 5} \) - \( \frac{8 x 1}{10 x 1} \)

\( \frac{45}{10} \) - \( \frac{8}{10} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{45 - 8}{10} \) = \( \frac{37}{10} \) = 3\(\frac{7}{10}\)

By buying two shirts, Alex will save $37 x \( \frac{10}{100} \) = \( \frac{$37 x 10}{100} \) = \( \frac{$370}{100} \) = $3.70 on the second shirt.

So, his total cost will be
$37.00 + ($37.00 - $3.70)
$37.00 + $33.30
$70.30

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(c³)⁴
c^{(3 * 4)}
c¹²