| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.43 |
| Score | 0% | 69% |
What is \( \frac{12\sqrt{35}}{4\sqrt{5}} \)?
| 7 \( \sqrt{3} \) | |
| 3 \( \sqrt{7} \) | |
| \(\frac{1}{7}\) \( \sqrt{3} \) | |
| \(\frac{1}{3}\) \( \sqrt{\frac{1}{7}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{12\sqrt{35}}{4\sqrt{5}} \)
\( \frac{12}{4} \) \( \sqrt{\frac{35}{5}} \)
3 \( \sqrt{7} \)
Diane scored 90% on her final exam. If each question was worth 3 points and there were 90 possible points on the exam, how many questions did Diane answer correctly?
| 39 | |
| 38 | |
| 27 | |
| 17 |
Diane scored 90% on the test meaning she earned 90% of the possible points on the test. There were 90 possible points on the test so she earned 90 x 0.9 = 81 points. Each question is worth 3 points so she got \( \frac{81}{3} \) = 27 questions right.
On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 35% of his shots. If the guard takes 25 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 20 | |
| 27 | |
| 23 | |
| 35 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{35}{100} \) = \( \frac{35 x 25}{100} \) = \( \frac{875}{100} \) = 8 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{8}{\frac{30}{100}} \) = 8 x \( \frac{100}{30} \) = \( \frac{8 x 100}{30} \) = \( \frac{800}{30} \) = 27 shots
to make the same number of shots as the guard and thus score the same number of points.
What is (b3)5?
| 3b5 | |
| b15 | |
| b-2 | |
| b8 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b3)5What is the next number in this sequence: 1, 9, 17, 25, 33, __________ ?
| 41 | |
| 50 | |
| 38 | |
| 42 |
The equation for this sequence is:
an = an-1 + 8
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 8
a6 = 33 + 8
a6 = 41