| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.69 |
| Score | 0% | 54% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Bob buys two shirts, each with a regular price of $23, how much will he pay for both shirts?
| $6.90 | |
| $26.45 | |
| $16.10 | |
| $39.10 |
By buying two shirts, Bob will save $23 x \( \frac{30}{100} \) = \( \frac{$23 x 30}{100} \) = \( \frac{$690}{100} \) = $6.90 on the second shirt.
So, his total cost will be
$23.00 + ($23.00 - $6.90)
$23.00 + $16.10
$39.10
A bread recipe calls for 2\(\frac{1}{4}\) cups of flour. If you only have \(\frac{1}{4}\) cup, how much more flour is needed?
| 2 cups | |
| 3\(\frac{1}{8}\) cups | |
| 2\(\frac{3}{8}\) cups | |
| 1\(\frac{7}{8}\) cups |
The amount of flour you need is (2\(\frac{1}{4}\) - \(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{18}{8} \) - \( \frac{2}{8} \)) cups
\( \frac{16}{8} \) cups
2 cups
Christine scored 85% on her final exam. If each question was worth 3 points and there were 300 possible points on the exam, how many questions did Christine answer correctly?
| 92 | |
| 85 | |
| 97 | |
| 89 |
Christine scored 85% on the test meaning she earned 85% of the possible points on the test. There were 300 possible points on the test so she earned 300 x 0.85 = 255 points. Each question is worth 3 points so she got \( \frac{255}{3} \) = 85 questions right.
The total water usage for a city is 50,000 gallons each day. Of that total, 22% is for personal use and 49% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 9,800 | |
| 7,249 | |
| 8,000 | |
| 13,500 |
49% of the water consumption is industrial use and 22% is personal use so (49% - 22%) = 27% more water is used for industrial purposes. 50,000 gallons are consumed daily so industry consumes \( \frac{27}{100} \) x 50,000 gallons = 13,500 gallons.
What is \( 2 \)\( \sqrt{32} \) + \( 5 \)\( \sqrt{2} \)
| 7\( \sqrt{64} \) | |
| 13\( \sqrt{2} \) | |
| 10\( \sqrt{16} \) | |
| 7\( \sqrt{32} \) |
To add these radicals together their radicands must be the same:
2\( \sqrt{32} \) + 5\( \sqrt{2} \)
2\( \sqrt{16 \times 2} \) + 5\( \sqrt{2} \)
2\( \sqrt{4^2 \times 2} \) + 5\( \sqrt{2} \)
(2)(4)\( \sqrt{2} \) + 5\( \sqrt{2} \)
8\( \sqrt{2} \) + 5\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
8\( \sqrt{2} \) + 5\( \sqrt{2} \)