ASVAB Arithmetic Reasoning Practice Test 1816 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

What is \( \frac{2}{5} \) x \( \frac{4}{9} \)?

72% Answer Correctly
\(\frac{3}{10}\)
1\(\frac{3}{5}\)
\(\frac{8}{45}\)
\(\frac{1}{16}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{5} \) x \( \frac{4}{9} \) = \( \frac{2 x 4}{5 x 9} \) = \( \frac{8}{45} \) = \(\frac{8}{45}\)


2

What is \( \sqrt{\frac{25}{9}} \)?

70% Answer Correctly
\(\frac{3}{4}\)
1\(\frac{2}{3}\)
1
\(\frac{3}{8}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{25}{9}} \)
\( \frac{\sqrt{25}}{\sqrt{9}} \)
\( \frac{\sqrt{5^2}}{\sqrt{3^2}} \)
\( \frac{5}{3} \)
1\(\frac{2}{3}\)


3

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for division

commutative property for multiplication

distributive property for multiplication

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


4

A bread recipe calls for 3\(\frac{1}{8}\) cups of flour. If you only have \(\frac{1}{8}\) cup, how much more flour is needed?

62% Answer Correctly
3 cups
1\(\frac{1}{4}\) cups
2 cups
1\(\frac{3}{4}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{8}\) - \(\frac{1}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{25}{8} \) - \( \frac{1}{8} \)) cups
\( \frac{24}{8} \) cups
3 cups


5

If all of a roofing company's 8 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?

55% Answer Correctly
12
13
8
4

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 4 crews so there are \( \frac{8}{4} \) = 2 workers on a crew. 6 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 6 x 2 = 12 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 12 - 8 = 4 new staff for the busy season.