ASVAB Arithmetic Reasoning Practice Test 182459 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

Simplify \( \sqrt{18} \)

62% Answer Correctly
6\( \sqrt{2} \)
3\( \sqrt{2} \)
9\( \sqrt{2} \)
7\( \sqrt{2} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{18} \)
\( \sqrt{9 \times 2} \)
\( \sqrt{3^2 \times 2} \)
3\( \sqrt{2} \)


2

Convert b-3 to remove the negative exponent.

68% Answer Correctly
\( \frac{1}{b^3} \)
\( \frac{-3}{-b} \)
\( \frac{-1}{-3b} \)
\( \frac{-1}{-3b^{3}} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


3

Cooks are needed to prepare for a large party. Each cook can bake either 4 large cakes or 19 small cakes per hour. The kitchen is available for 3 hours and 28 large cakes and 250 small cakes need to be baked.

How many cooks are required to bake the required number of cakes during the time the kitchen is available?

41% Answer Correctly
9
7
8
5

Solution

If a single cook can bake 4 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 4 x 3 = 12 large cakes during that time. 28 large cakes are needed for the party so \( \frac{28}{12} \) = 2\(\frac{1}{3}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 19 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 19 x 3 = 57 small cakes during that time. 250 small cakes are needed for the party so \( \frac{250}{57} \) = 4\(\frac{22}{57}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 3 + 5 = 8 cooks.


4

Which of these numbers is a factor of 40?

69% Answer Correctly
10
28
34
7

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 40 are 1, 2, 4, 5, 8, 10, 20, 40.


5

Solve 2 + (2 + 3) ÷ 5 x 2 - 32

53% Answer Correctly
\(\frac{1}{3}\)
1\(\frac{1}{2}\)
\(\frac{7}{9}\)
-5

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (2 + 3) ÷ 5 x 2 - 32
P: 2 + (5) ÷ 5 x 2 - 32
E: 2 + 5 ÷ 5 x 2 - 9
MD: 2 + \( \frac{5}{5} \) x 2 - 9
MD: 2 + \( \frac{10}{5} \) - 9
AS: \( \frac{10}{5} \) + \( \frac{10}{5} \) - 9
AS: \( \frac{20}{5} \) - 9
AS: \( \frac{20 - 45}{5} \)
\( \frac{-25}{5} \)
-5