| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
Ezra loaned Damon $700 at an annual interest rate of 8%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $48 | |
| $18 | |
| $7 | |
| $56 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $700
i = 0.08 x $700
i = $56
A factor is a positive __________ that divides evenly into a given number.
improper fraction |
|
fraction |
|
mixed number |
|
integer |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
If a rectangle is twice as long as it is wide and has a perimeter of 30 meters, what is the area of the rectangle?
| 50 m2 | |
| 128 m2 | |
| 18 m2 | |
| 162 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 30 meters so the equation becomes: 2w + 2h = 30.
Putting these two equations together and solving for width (w):
2w + 2h = 30
w + h = \( \frac{30}{2} \)
w + h = 15
w = 15 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 15 - 2w
3w = 15
w = \( \frac{15}{3} \)
w = 5
Since h = 2w that makes h = (2 x 5) = 10 and the area = h x w = 5 x 10 = 50 m2
A machine in a factory has an error rate of 3 parts per 100. The machine normally runs 24 hours a day and produces 10 parts per hour. Yesterday the machine was shut down for 7 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 180.5 | |
| 115.2 | |
| 193.2 | |
| 164.9 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{3}{100} \) x 10 = \( \frac{3 \times 10}{100} \) = \( \frac{30}{100} \) = 0.3 errors per hour
So, in an average hour, the machine will produce 10 - 0.3 = 9.7 error free parts.
The machine ran for 24 - 7 = 17 hours yesterday so you would expect that 17 x 9.7 = 164.9 error free parts were produced yesterday.
What is \( \frac{2z^9}{9z^3} \)?
| \(\frac{2}{9}\)z6 | |
| 4\(\frac{1}{2}\)z6 | |
| \(\frac{2}{9}\)z3 | |
| 4\(\frac{1}{2}\)z-6 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{2z^9}{9z^3} \)
\( \frac{2}{9} \) z(9 - 3)
\(\frac{2}{9}\)z6