| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
If a mayor is elected with 64% of the votes cast and 54% of a town's 49,000 voters cast a vote, how many votes did the mayor receive?
| 16,934 | |
| 15,876 | |
| 23,814 | |
| 20,110 |
If 54% of the town's 49,000 voters cast ballots the number of votes cast is:
(\( \frac{54}{100} \)) x 49,000 = \( \frac{2,646,000}{100} \) = 26,460
The mayor got 64% of the votes cast which is:
(\( \frac{64}{100} \)) x 26,460 = \( \frac{1,693,440}{100} \) = 16,934 votes.
Ezra loaned Monica $200 at an annual interest rate of 8%. If no payments are made, what is the total amount owed at the end of the first year?
| $204 | |
| $218 | |
| $214 | |
| $216 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $200
i = 0.08 x $200
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $200 + $16
| 7.0 | |
| 1 | |
| 2.8 | |
| 5.4 |
1
Simplify \( \frac{32}{56} \).
| \( \frac{2}{9} \) | |
| \( \frac{4}{7} \) | |
| \( \frac{2}{3} \) | |
| \( \frac{8}{15} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 56 are [1, 2, 4, 7, 8, 14, 28, 56]. They share 4 factors [1, 2, 4, 8] making 8 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{32}{56} \) = \( \frac{\frac{32}{8}}{\frac{56}{8}} \) = \( \frac{4}{7} \)
What is \( \frac{7}{5} \) + \( \frac{3}{9} \)?
| 1\(\frac{11}{15}\) | |
| 1 \( \frac{1}{9} \) | |
| 2 \( \frac{4}{45} \) | |
| 1 \( \frac{6}{13} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 9}{5 x 9} \) + \( \frac{3 x 5}{9 x 5} \)
\( \frac{63}{45} \) + \( \frac{15}{45} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{63 + 15}{45} \) = \( \frac{78}{45} \) = 1\(\frac{11}{15}\)