ASVAB Arithmetic Reasoning Practice Test 186874 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

If all of a roofing company's 12 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 9 complete crews out on jobs?

55% Answer Correctly
15
18
8
13

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 4 crews so there are \( \frac{12}{4} \) = 3 workers on a crew. 9 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 9 x 3 = 27 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 27 - 12 = 15 new staff for the busy season.


2

If there were a total of 250 raffle tickets sold and you bought 5 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
6%
18%
2%
4%

Solution

You have 5 out of the total of 250 raffle tickets sold so you have a (\( \frac{5}{250} \)) x 100 = \( \frac{5 \times 100}{250} \) = \( \frac{500}{250} \) = 2% chance to win the raffle.


3

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for division

commutative property for division

commutative property for multiplication

distributive property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


4

In a class of 23 students, 8 are taking German and 11 are taking Spanish. Of the students studying German or Spanish, 2 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
12
18
6
16

Solution

The number of students taking German or Spanish is 8 + 11 = 19. Of that group of 19, 2 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 19 - 2 = 17 who are taking at least one language. 23 - 17 = 6 students who are not taking either language.


5

Which of the following is not an integer?

77% Answer Correctly

0

1

\({1 \over 2}\)

-1


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.