| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.84 |
| Score | 0% | 57% |
Bob loaned Jennifer $1,300 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,365 | |
| $1,352 | |
| $1,313 | |
| $1,339 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,300
i = 0.03 x $1,300
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,300 + $39How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 10 gallon tank to fill it exactly halfway?
| 2 | |
| 7 | |
| 3 | |
| 4 |
To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{5 \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 2
What is 9\( \sqrt{2} \) x 2\( \sqrt{7} \)?
| 18\( \sqrt{14} \) | |
| 11\( \sqrt{2} \) | |
| 18\( \sqrt{2} \) | |
| 11\( \sqrt{7} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
9\( \sqrt{2} \) x 2\( \sqrt{7} \)
(9 x 2)\( \sqrt{2 \times 7} \)
18\( \sqrt{14} \)
Solve 4 + (3 + 5) ÷ 2 x 2 - 32
| 1\(\frac{2}{5}\) | |
| \(\frac{1}{3}\) | |
| 1 | |
| 3 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (3 + 5) ÷ 2 x 2 - 32
P: 4 + (8) ÷ 2 x 2 - 32
E: 4 + 8 ÷ 2 x 2 - 9
MD: 4 + \( \frac{8}{2} \) x 2 - 9
MD: 4 + \( \frac{16}{2} \) - 9
AS: \( \frac{8}{2} \) + \( \frac{16}{2} \) - 9
AS: \( \frac{24}{2} \) - 9
AS: \( \frac{24 - 18}{2} \)
\( \frac{6}{2} \)
3
What is \( \frac{3}{8} \) ÷ \( \frac{4}{6} \)?
| \(\frac{2}{63}\) | |
| 4\(\frac{1}{2}\) | |
| \(\frac{9}{16}\) | |
| \(\frac{1}{7}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{3}{8} \) ÷ \( \frac{4}{6} \) = \( \frac{3}{8} \) x \( \frac{6}{4} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{8} \) x \( \frac{6}{4} \) = \( \frac{3 x 6}{8 x 4} \) = \( \frac{18}{32} \) = \(\frac{9}{16}\)