| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.53 |
| Score | 0% | 71% |
19 members of a bridal party need transported to a wedding reception but there are only 4 4-passenger taxis available to take them. How many will need to find other transportation?
| 3 | |
| 2 | |
| 6 | |
| 1 |
There are 4 4-passenger taxis available so that's 4 x 4 = 16 total seats. There are 19 people needing transportation leaving 19 - 16 = 3 who will have to find other transportation.
Roger loaned Monty $900 at an annual interest rate of 7%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $105 | |
| $24 | |
| $63 | |
| $98 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $900
i = 0.07 x $900
i = $63
4! = ?
4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
|
4 x 3 |
|
5 x 4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
Simplify \( \sqrt{32} \)
| 3\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) | |
| 3\( \sqrt{4} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{32} \)
\( \sqrt{16 \times 2} \)
\( \sqrt{4^2 \times 2} \)
4\( \sqrt{2} \)
A tiger in a zoo has consumed 28 pounds of food in 4 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 70 pounds?
| 6 | |
| 10 | |
| 7 | |
| 5 |
If the tiger has consumed 28 pounds of food in 4 days that's \( \frac{28}{4} \) = 7 pounds of food per day. The tiger needs to consume 70 - 28 = 42 more pounds of food to reach 70 pounds total. At 7 pounds of food per day that's \( \frac{42}{7} \) = 6 more days.